12y^2+19y+4=

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Solution for 12y^2+19y+4= equation:


Simplifying
12y2 + 19y + 4 = 0

Reorder the terms:
4 + 19y + 12y2 = 0

Solving
4 + 19y + 12y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(4 + 3y)(1 + 4y) = 0

Subproblem 1

Set the factor '(4 + 3y)' equal to zero and attempt to solve: Simplifying 4 + 3y = 0 Solving 4 + 3y = 0 Move all terms containing y to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + 3y = 0 + -4 Combine like terms: 4 + -4 = 0 0 + 3y = 0 + -4 3y = 0 + -4 Combine like terms: 0 + -4 = -4 3y = -4 Divide each side by '3'. y = -1.333333333 Simplifying y = -1.333333333

Subproblem 2

Set the factor '(1 + 4y)' equal to zero and attempt to solve: Simplifying 1 + 4y = 0 Solving 1 + 4y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 4y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 4y = 0 + -1 4y = 0 + -1 Combine like terms: 0 + -1 = -1 4y = -1 Divide each side by '4'. y = -0.25 Simplifying y = -0.25

Solution

y = {-1.333333333, -0.25}

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